ralentizando la velocidad del bucle for

Question

for(;;) { 
    int rand_number = rand() % 2; 
    cout << rand_number; 
} 

Estos bucles generan los 1 y 0 en la pantalla como la película matricial (LOL) pero el código se ejecuta muy rápido ¿hay alguna forma de hacer que los números aparezcan lentamente?

Answer 1

uso Sleep(3000); que esperar a 3000 milisegundos por ejemplo

#include <iostream> 
#include <stdlib.h> 
#include <Windows.h> 

using namespace std; 

int main(int argc,char**argv){ 
    cout<<"a"<<endl; 
    Sleep(3000); 
    cout<<"b"<<endl; 

    return 0; 
} 

Answer 2

Echa un vistazo usleep. También podrías usar el sueño, pero imagino que será demasiado lento.

USLEEP(3)    BSD Library Functions Manual    USLEEP(3) 

NAME 
    usleep -- suspend thread execution for an interval measured in microseconds 

LIBRARY 
    Standard C Library (libc, -lc) 

SYNOPSIS 
    #include <unistd.h> 

    int 
    usleep(useconds_t useconds); 

DESCRIPTION 
    The usleep() function suspends execution of the calling thread until either useconds microseconds have elapsed or a signal is delivered to the thread whose action 
    is to invoke a signal-catching function or to terminate the thread or process. The actual time slept may be longer, due to system latencies and possible limita- 
    tions in the timer resolution of the hardware. 

    This function is implemented, using nanosleep(2), by pausing for useconds microseconds or until a signal occurs. Consequently, in this implementation, sleeping 
    has no effect on the state of process timers and there is no special handling for SIGALRM. 

RETURN VALUES 
    The usleep() function returns the value 0 if successful; otherwise the value -1 is returned and the global variable errno is set to indicate the error. 

ERRORS 
    The usleep() function will fail if: 

    [EINTR]   A signal was delivered to the process and its action was to invoke a signal-catching function. 

SEE ALSO 
    nanosleep(2), sleep(3) 

HISTORY 
    The usleep() function appeared in 4.3BSD. 

BSD       February 13, 1998       BSD 

Answer 3

Si lo que desea es que se detenga hasta que esté listo se puede poner en un sentido cin al azar. Solo esperará allí para ingresar hasta que presione regresar.