Tengo un conjunto de 4 tablas en las que quiero buscar. Cada uno tiene un índice de texto completo. ¿Puede una consulta hacer uso de cada índice?mySQL MATCH en varias tablas
CREATE TABLE `categories` (
`id` int(5) unsigned NOT NULL auto_increment,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=latin1;
CREATE TABLE `host_types` (
`id` int(5) unsigned NOT NULL auto_increment,
`category_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`category_id`,`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
CREATE TABLE `hosts` (
`id` int(5) unsigned NOT NULL auto_increment,
`host_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`host_id`,`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=latin1;
CREATE TABLE `products` (
`id` int(11) unsigned NOT NULL auto_increment,
`host_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`uid` varchar(10) default NULL,
`name` varchar(128) default NULL,
`keywords` text,
`description` text,
`price` decimal(10,2) default NULL,
`quantity` int(11) unsigned default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
FULLTEXT KEY `full_name` (`name`,`keywords`,`description`,`uid`)
) ENGINE=MyISAM AUTO_INCREMENT=14 DEFAULT CHARSET=latin1;
Aquí está mi consulta;
SELECT categories.name AS category,
categories.id AS category_id,
host_types.name AS host_type,
host_types.id AS host_type_id,
hosts.name AS host,
hosts.id AS host_id,
products.name as name,
products.id AS product_id,
products.keywords as keywords,
products.description AS description,
products.quantity AS quantity,
products.price AS price,
products.uid as catalogue,
MATCH(categories.name, host_types.name, hosts.name, products.name,
products.keywords, products.description, products.uid)
AGAINST('search term') as score
FROM products
LEFT JOIN hosts ON products.host_id = hosts.id
LEFT JOIN host_types ON hosts.host_id = host_types.id
LEFT JOIN categories ON host_types.category_id = categories.id
WHERE MATCH(categories.name, host_types.name, hosts.name, products.name,
products.keywords, products.description, products.uid)
AGAINST('search term')
ORDER BY score DESC;
- categories.name == FULLTEXT - 1
- host_types.name == FULLTEXT - 2
- hosts.name == FULLTEXT - 3
- products.name, products.keywords, products.description, products.uid FULLTEXT == - 4
Aquí está mi estructura SQL, y Usé la consulta anterior.
SELECT
categories.name AS category,
categories.id AS category_id,
host_types.name AS host_type,
host_types.id AS host_type_id,
hosts.name AS host,
hosts.id AS host_id,
products.name as name,
products.id AS product_id,
products.keywords as keywords,
products.description AS description,
products.quantity AS quantity,
products.price AS price,
products.uid as catalgue
MATCH(categories.name) AGAINST('search term') as cscore,
MATCH(host_types.name) AGAINST('search term') as htscore,
MATCH(hosts.name) AGAINST('search term') as hscore,
MATCH(products.name, products.keywords, products.description, products.uid)
AGAINST('search term') as score
FROM products
LEFT JOIN hosts ON products.host_id = hosts.id
LEFT JOIN host_types ON hosts.host_id = host_types.id
LEFT JOIN categories ON host_types.category_id = categories.id
WHERE
MATCH(categories.name) AGAINST('search term') OR
MATCH(host_types.name) AGAINST('search term') OR
MATCH(hosts.name) AGAINST('search term') OR
MATCH(products.name, products.keywords, products.description, products.uid)
AGAINST('search term')
ORDER BY score DESC
CREATE TABLE `categories` (
`id` int(5) unsigned NOT NULL auto_increment,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=latin1;
CREATE TABLE `host_types` (
`id` int(5) unsigned NOT NULL auto_increment,
`category_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`category_id`,`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
CREATE TABLE `hosts` (
`id` int(5) unsigned NOT NULL auto_increment,
`host_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`name` varchar(64) default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `order` (`host_id`,`display_order`),
FULLTEXT KEY `full_name` (`name`)
) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=latin1;
CREATE TABLE `products` (
`id` int(11) unsigned NOT NULL auto_increment,
`host_id` int(5) unsigned default NULL,
`display_order` int(5) unsigned default NULL,
`uid` varchar(10) default NULL,
`name` varchar(128) default NULL,
`keywords` text,
`description` text,
`price` decimal(10,2) default NULL,
`quantity` int(11) unsigned default NULL,
`last_modified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
FULLTEXT KEY `full_name` (`name`,`keywords`,`description`,`uid`)
) ENGINE=MyISAM AUTO_INCREMENT=14 DEFAULT CHARSET=latin1;
+50 a la persona que responde a esta pregunta ... .. . correctamente – Dirk
Por un segundo parece que está teniendo un show-off de sql-query más largo. –
Lo edité con la esperanza de encontrar una pregunta ... ¿es un acertijo? –