Cálculo del número de años entre 2 fechas en PHP

Question

Necesito obtener el número de años a partir de 2 fechas proporcionadas. Aquí está mi código:

function daysDifference($endDate, $beginDate) 
{ 
    $date_parts1=explode("-", $beginDate); 
    $date_parts2=explode("-", $endDate); 

    $start_date=gregoriantojd($date_parts1[1], $date_parts1[2], $date_parts1[0]); 
    $end_date=gregoriantojd($date_parts2[1], $date_parts2[2], $date_parts2[0]); 
    $diff = $end_date - $start_date; 
    echo $diff; 
    $years = floor($diff/(365.25*60*60*24)); 
    return $years; 
} 

echo daysDifference('2011-03-12','2008-03-09'); 

El $diff da una salida numérica. Cuando regreso $years, obtengo 0. ¿Qué he hecho mal?

Answer 1

Si desea que el número de años entre dos fechas, ¿por qué no usar lo siguiente:

function yearsDifference($endDate, $beginDate) 
{ 
    $date_parts1=explode("-", $beginDate); 
    $date_parts2=explode("-", $endDate); 
    return $date_parts2[0] - $date_parts1[0]; 
} 

echo yearsDifference('2011-03-12','2008-03-09'); 

que, en este caso, le conseguirá:

3 

Answer 2

$d1 = new DateTime('2011-03-12'); 
$d2 = new DateTime('2008-03-09'); 

$diff = $d2->diff($d1); 

echo $diff->y; 

Answer 3

la El valor de $ start_date y $ end_date es la cantidad de días, no segundos. por lo tanto, no debe dividir el $ diff con 365.25 * 60 * 60 * 24.

function daysDifference($endDate, $beginDate) 
{ 

    $date_parts1 = explode("-", $beginDate); 
    $date_parts2 = explode("-", $endDate); 
    $start_date = gregoriantojd($date_parts1[1], $date_parts1[2], $date_parts1[0]); 
    $end_date = gregoriantojd($date_parts2[1], $date_parts2[2], $date_parts2[0]); 
    $diff = abs($end_date - $start_date); 
    $years = floor($diff/365.25); 
    return $years; 
} 

echo daysDifference('2011-03-12','2008-03-09'); 

Answer 4

chicos aquí hay un buen código Solía ​​usar ..... no es mi idea .... yo acabamos de que en algún lugar de la red ...

También tienen una variedad de opciones espero que esta ayuda .........

function datediff($interval, $datefrom, $dateto, $using_timestamps = false) { 
    /* 
    $interval can be: 
    yyyy - Number of full years 
    q - Number of full quarters 
    m - Number of full months 
    y - Difference between day numbers 
     (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".) 
    d - Number of full days 
    w - Number of full weekdays 
    ww - Number of full weeks 
    h - Number of full hours 
    n - Number of full minutes 
    s - Number of full seconds (default) 
    */ 

    if (!$using_timestamps) { 
     $datefrom = strtotime($datefrom, 0); 
     $dateto = strtotime($dateto, 0); 
    } 
    $difference = $dateto - $datefrom; // Difference in seconds 

    switch($interval) { 

    case 'yyyy': // Number of full years 

     $years_difference = floor($difference/31536000); 
     if (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom), date("j", $datefrom), date("Y", $datefrom)+$years_difference) > $dateto) { 
      $years_difference--; 
     } 
     if (mktime(date("H", $dateto), date("i", $dateto), date("s", $dateto), date("n", $dateto), date("j", $dateto), date("Y", $dateto)-($years_difference+1)) > $datefrom) { 
      $years_difference++; 
     } 
     $datediff = $years_difference; 
     break; 

    case "q": // Number of full quarters 

     $quarters_difference = floor($difference/8035200); 
     while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($quarters_difference*3), date("j", $dateto), date("Y", $datefrom)) < $dateto) { 
      $months_difference++; 
     } 
     $quarters_difference--; 
     $datediff = $quarters_difference; 
     break; 

    case "m": // Number of full months 

     $months_difference = floor($difference/2678400); 
     while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($months_difference), date("j", $dateto), date("Y", $datefrom)) < $dateto) { 
      $months_difference++; 
     } 
     $months_difference--; 
     $datediff = $months_difference; 
     break; 

    case 'y': // Difference between day numbers 

     $datediff = date("z", $dateto) - date("z", $datefrom); 
     break; 

    case "d": // Number of full days 

     $datediff = floor($difference/86400); 
     break; 

    case "w": // Number of full weekdays 

     $days_difference = floor($difference/86400); 
     $weeks_difference = floor($days_difference/7); // Complete weeks 
     $first_day = date("w", $datefrom); 
     $days_remainder = floor($days_difference % 7); 
     $odd_days = $first_day + $days_remainder; // Do we have a Saturday or Sunday in the remainder? 
     if ($odd_days > 7) { // Sunday 
      $days_remainder--; 
     } 
     if ($odd_days > 6) { // Saturday 
      $days_remainder--; 
     } 
     $datediff = ($weeks_difference * 5) + $days_remainder; 
     break; 

    case "ww": // Number of full weeks 

     $datediff = floor($difference/604800); 
     break; 

    case "h": // Number of full hours 

     $datediff = floor($difference/3600); 
     break; 

    case "n": // Number of full minutes 

     $datediff = floor($difference/60); 
     break; 

    default: // Number of full seconds (default) 

     $datediff = $difference; 
     break; 
    }  

    return $datediff; 

} 

echo datediff('yyyy','2009-01-16','2011-03-16'); 

Answer 5

En una caja de PHP 5.2 (sí realmente, todavía existen) así que sin DateTime :: diff() de soporte que terminé usando esto:

$dateString='10-05-1975'; 
$years = round((time()-strtotime($dateString))/(3600*24*365.25)) 

Answer 6

<?php 

$date1=date_create("1992-02-22");  

$date2=date_create("2016-09-24");  

$diff=date_diff($date1,$date2);  

echo $diff->y;  

?> 

Creo que esta es la mejor respuesta que he usado.

Gracias