Python - error de tipo irresistible en urllib2

Question

>> url = 'https://test.authorize.net/gateway/transact.dll' 
>> data = {'x_login': 'abc123', 'x_type': 'AUTH_CAPTURE', 'x_card_num': '4444333322221103', 'x_amount': '50.75', 'x_tran_key 
': 'abc123', 'x_version': '3.1', 'x_delim_char': '|', 'x_exp_date': '022012', 'x_delim_data': 'TRUE'} 
>> 
>> urllib2.urlopen(url, data) 
Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "gateways\base.py", line 81, in dispatch 
    return gw_method(self, *args, **kwargs) 
    File "gateways\decorators.py", line 17, in wrapper 
    method(*args, **kwargs) 
    File "gateways\authorize_net.py", line 39, in auth_capture 
    return self.post_data(data) 
    File "gateways\authorize_net.py", line 43, in post_data 
    raw_response = urllib2.urlopen(self.get_endpoint(), data) 
    File "C:\Python26\lib\urllib2.py", line 124, in urlopen 
    return _opener.open(url, data, timeout) 
    File "C:\Python26\lib\urllib2.py", line 389, in open 
    response = self._open(req, data) 
    File "C:\Python26\lib\urllib2.py", line 407, in _open 
    '_open', req) 
    File "C:\Python26\lib\urllib2.py", line 367, in _call_chain 
    result = func(*args) 
    File "C:\Python26\lib\urllib2.py", line 1154, in https_open 
    return self.do_open(httplib.HTTPSConnection, req) 
    File "C:\Python26\lib\urllib2.py", line 1118, in do_open 
    h.request(req.get_method(), req.get_selector(), req.data, headers) 
    File "C:\Python26\lib\httplib.py", line 898, in request 
    self._send_request(method, url, body, headers) 
    File "C:\Python26\lib\httplib.py", line 938, in _send_request 
    self.send(body) 
    File "C:\Python26\lib\httplib.py", line 743, in send 
    self.sock.sendall(str) 
    File "C:\Python26\lib\ssl.py", line 203, in sendall 
    v = self.send(data[count:]) 
TypeError: unhashable type 

No puedo entender qué causó este error.

Answer 1

data se supone que es un "buffer en el formato de aplicación estándar/x-www-form-urlencoded.", No es un dict.

Antes de pasar el dict de datos en hacer data = urllib.urlencode(data), para que obtenga el formato correcto de su dict.

Answer 2

También puede usar lo siguiente si está usando json.

json.dumps(data) 

Recuerde: urlencode puede codificar un dict, pero no una cadena. La salida de json.dumps es una cadena.