Servidor SQL: ¿cómo obtener atributos XML en una consulta?

Question

Actualmente estoy tratando de obtener todos los atributos de algunos XML con una consulta SQL.

He estado intentando lo siguiente para recuperarlo, pero me falta algo fundamental.

DECLARE @T varchar(max) 
SET @T = 
'<root> 
    <Field FieldRowId="1000"> 
    <Items> 
     <Item Name="CODE"/> 
     <Item Name="DATE"/> 
    </Items> 
     <Attributes> 
     <Attribute ID ="1"/> 
     </Attributes> 
    </Field> 
    <Field FieldRowId="2000"> 
    <Items> 
       <Item Name="CODE"/> 
       <Item Name="DATE"/> 
    </Items> 
    <Attributes> 
     <Attribute ID ="2"/> 
    </Attributes> 
    </Field> 
</root>' 

DECLARE @X xml 

SET @X = CAST(@T as xml) 
SELECT Y.ID.value('@FieldRowId', 'int') as FieldID, 
    Y.ID.value('/Items/@Name', 'varchar(max)') as "Name", 
    Y.ID.value('/Attributes/@ID', 'int') as AttributeID 
FROM @X.nodes('/root/Field') as Y(ID) 

Answer 1

Usted tendría que intentar algo como esto: (el atributo @Name está en el elemento "artículo" - no a los "Artículos"!)

SET @X = CAST(@T as xml) 
SELECT 
    Y.ID.value('(@FieldRowId)[1]', 'int') as FieldID, 
    Y.ID.value('(Items/Item/@Name)[1]', 'varchar(max)') as "Name", 
    Y.ID.value('(Attributes/Attribute/@ID)[1]', 'int') as AttributeID 
FROM @X.nodes('/root/Field') as Y(ID) 

Marc

Answer 2

SELECT t1.fieldId, name, attributeId 
FROM (SELECT Y.ID.value('../../@FieldRowId', 'int') as FieldID 
    , Y.ID.value('@Name', 'varchar(max)') as Name  
FROM @T.nodes('(/root/Field/Items/Item)') as Y(ID) 
) t1 -- alias the first result 
JOIN 
(SELECT Y.ID.value('../../@FieldRowId', 'int') as FieldID 
    , Y.ID.value('@ID', 'int') as AttributeID 
FROM @T.nodes('(/root/Field/Attributes/Attribute)') as Y(ID) 
) t2 -- alias the second result 
on t1.fieldid = t2.FieldID -- join them on a common column