2011-11-11 15 views
5

he utilizado con éxito en this solutionandroide publicar en HTTPS aceptar todos los certificadosconexión con https con httpclient 4.1.2 da org.apache.http.client.ClientProtocolException

Ahora estoy intentando lo mismo en JAVA para publicar en el servidor https aceptando todos los certificados.

Modifiqué la clase EasySSLSocketFactory de la URL anterior ya que las clases SocketFactory, LayeredSocketFactory están en desuso en la versión httpclient 4.1.2. EasyX509TrustManager La clase de la url anterior no cambia. Aquí está el EasySSLSocketFactory que he modificado. He marcado las clases que he modificado.

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import java.io.IOException; 
import java.net.InetSocketAddress; 
import java.net.Socket; 
import java.net.UnknownHostException; 

import javax.net.ssl.SSLContext; 
import javax.net.ssl.SSLSocket; 
import javax.net.ssl.TrustManager; 

import org.apache.http.conn.ConnectTimeoutException; 
import org.apache.http.conn.scheme.SchemeSocketFactory; 
import org.apache.http.params.HttpConnectionParams; 
import org.apache.http.params.HttpParams; 


public class EasySSLSocketFactory implements SchemeSocketFactory 
{ 
    private SSLContext sslcontext = null; 

    private static SSLContext createEasySSLContext() throws IOException { 
      try { 
        SSLContext context = SSLContext.getInstance("TLS"); 
        context.init(null, new TrustManager[] { new EasyX509TrustManager(null) }, null); 
        return context; 
      } catch (Exception e) { 
        throw new IOException(e.getMessage()); 
      } 
    } 


    private SSLContext getSSLContext() throws IOException { 
      if (this.sslcontext == null) { 
        this.sslcontext = createEasySSLContext(); 
      } 
      return this.sslcontext; 
    } 

    /** 
     * @see org.apache.http.conn.scheme.SchemeSocketFactory#isSecure(java.net.Socket) 
     */ 
    public boolean isSecure(Socket socket) throws IllegalArgumentException { 
      return true; 
    } 

    // ------------------------------------------------------------------- 
    // javadoc in org.apache.http.conn.scheme.SocketFactory says : 
    // Both Object.equals() and Object.hashCode() must be overridden 
    // for the correct operation of some connection managers 
    // ------------------------------------------------------------------- 

    public boolean equals(Object obj) { 
      return ((obj != null) && obj.getClass().equals(
          EasySSLSocketFactory.class)); 
    } 

    public int hashCode() { 
      return EasySSLSocketFactory.class.hashCode(); 
    } 

    //this method is modified 
    @Override 
    public Socket connectSocket(Socket sock, InetSocketAddress remoteAddress, 
      InetSocketAddress localAddress, HttpParams params) throws IOException, 
      UnknownHostException, ConnectTimeoutException { 

     int connTimeout = HttpConnectionParams.getConnectionTimeout(params); 
     int soTimeout = HttpConnectionParams.getSoTimeout(params); 
     SSLSocket sslsock = (SSLSocket) ((sock != null) ? sock : createSocket(params)); 
     if (localAddress != null) { 
      // we need to bind explicitly 
      sslsock.bind(localAddress); 
    } 

    sslsock.connect(remoteAddress, connTimeout); 
    sslsock.setSoTimeout(soTimeout); 
    return sslsock; 
    } 

    //this method is modified 
    @Override 
    public Socket createSocket(HttpParams arg0) throws IOException { 
     return getSSLContext().getSocketFactory().createSocket(); 
    } 

} 

Y aquí es mi clase httpclient.This también se modifica debido al uso de httpclient 4.1.2

public class MyHttpClient extends DefaultHttpClient { 

    /** The time it takes for our client to timeout */ 
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds 
    public static final int SOCKET_TIMEOUT = 50 * 1000; // milliseconds 


    public MyHttpClient() { 
    } 

    @Override 
    protected ClientConnectionManager createClientConnectionManager() { 

     SchemeRegistry registry = new SchemeRegistry(); 
     registry.register(new Scheme("http", 80, PlainSocketFactory.getSocketFactory())); 
     // Register for port 443 our SSLSocketFactory to the ConnectionManager 
     registry.register(new Scheme("https", 443, new EasySSLSocketFactory())); 

     //setting the httpparams 
     HttpParams params = new BasicHttpParams(); 
     //params.setParameter(ConnManagerPNames.MAX_TOTAL_CONNECTIONS, 1); 
     //params.setParameter(ConnManagerPNames.MAX_CONNECTIONS_PER_ROUTE, new ConnPerRouteBean(1)); 
     params.setParameter(HttpProtocolParams.USE_EXPECT_CONTINUE, false); 
     //HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1); 
     HttpProtocolParams.setContentCharset(params, "utf8"); 

     return new SingleClientConnManager(registry); 
    } 

} 

Estoy tratando de conectar de la siguiente manera

ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); 
     postParameters.add(new BasicNameValuePair("userid", userid)); 
     postParameters.add(new BasicNameValuePair("password", password)); 
     String newresponse = null; 
     BufferedReader in = null; 
     try{ 
      DefaultHttpClient client = new MyHttpClient(); 
      try {   
        HttpPost req = new HttpPost(my https url); 
        UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); 
        req.setEntity(formEntity); 
        HttpResponse resp = client.execute(req); 
        in = new BufferedReader(new InputStreamReader(resp.getEntity().getContent())); 
        StringBuffer sb = new StringBuffer(""); 
        String line = ""; 
        String NL = System.getProperty("line.separator"); 
        while ((line = in.readLine()) != null) { 
         sb.append(line + NL); 
        } 
        in.close(); 
        newresponse = sb.toString(); 

        }catch(Exception e){ 
         LOGGER.error("Exception", e); 
        }finally { 
         if (in != null) { 
          try { 
           in.close(); 
          } catch (IOException e) { 
           LOGGER.error("IOException: ",e); 
          } 
         } 
        } 
     } catch(Exception e){ 
      LOGGER.debug("Connection Exception: ",e); 
     } 

Cuando i tratar de conectarse al servidor https de la manera anterior me sale

org.apache.http.client.ClientProtocolException 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:822) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:754) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:732) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:641) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 
     at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:304) 
     at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) 
     at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240) 
     at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:164) 
     at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:576) 
     at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164) 
     at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100) 
     at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:563) 
     at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118) 
     at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:399) 
     at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:317) 
     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:204) 
     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:182) 
     at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:311) 
     at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) 
     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) 
     at java.lang.Thread.run(Thread.java:662) 
Caused by: org.apache.http.HttpException: Unable to establish route: planned = HttpRoute[{}->https://mysiteurlhere]; current = HttpRoute[{s}->https://mysiteurlhere] 
     at org.apache.http.impl.client.DefaultRequestDirector.establishRoute(DefaultRequestDirector.java:774) 
     at org.apache.http.impl.client.DefaultRequestDirector.tryConnect(DefaultRequestDirector.java:577) 
     at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:425) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:820) 
     ... 22 more 

El servidor que estoy tratando de acceder está usando el certificado de verisign que no tengo conmigo. Por lo tanto, estoy tratando de aceptar todos los certificados. En el futuro voy a cambiar esto.

¿Alguien puede hacerlo funcionar? Gracias de antemano.

Respuesta

4

Su EasySSLSocketFactory también debe implementar la interfaz LayeredSchemeSocketFactory si desea que admita túnel SSL.

+0

@ oleg- Gracias por la response.I que tratarán y te mantendrá informado. – Sreeram

+0

@ oleg- Intenté implementarlo y funciona como un amuleto. Muchísimas gracias. – Sreeram

0

También debe registrar Esquema de SSLSockerFactory:

httpClient.getConnectionManager().getSchemeRegistry().register(
    new Scheme("https", 443, SSLSocketFactory.getSystemSocketFactory()) 
); 
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