Un delegado de multidifusión es un delegado que tiene referencias a más de una función. Cuando invoca a un delegado de multidifusión, se invocan todas las funciones a las que apunta el delegado.
Tipo 1:
0 argumento y sin efecto tipo de retorno delegado -
Método 1 -
using System;
delegate void SampleDelegate(); //A delegate with 0 argument and void return type is declared
class MainClass
{
public static void Main()
{
SampleDelegate Del1 = new SampleDelegate (Message1); //Del1 declared which points to function Message1
SampleDelegate Del2 = new SampleDelegate (Message2); //Del2 declared which points to function Message2
SampleDelegate Del3 = new SampleDelegate (Message3); //Del3 declared which points to function Message3
SampleDelegate Del4 = Del1 + Del2 + Del3; //Del4 declared which points to function Message4
//Del4 is then initialized as sum of Del1 + Del2 + Del3
Del4(); //Del4 is invoked;
//Del4 in turn invokes Del1, Del2 and Del3 in the same order they were initialized to Del4
//Del1, Del2, Del3 in turn invokes their respective functions to which they point to
//The three functions Message1, Message2 and Message3 gets executed one after another
}
//Output:
//This is message 1
//This is message 2
//This is message 3
Del4 - Del1; //Removes Del1 from Del4
Del4();
//New Output:
//This is message 2
//This is message 3
Del4 + Del1; //Again adds Del1 to Del4
Del4();
//New Output:
//This is message 1
//This is message 2
//This is message 3
public static void Message1() //First sample function matching delegate signature
{
Console.WriteLine ("This is message 1");
}
public static void Message2() //Second sample function
{
Console.WriteLine ("This is message 2");
}
public static void Message3() //Third sample function
{
Console.WriteLine ("This is message 3");
}
}
Método 2 -
using System;
delegate void SampleDelegate();
class MainClass
{
public static void Main()
{
SampleDelegate del = new SampleDelegate (Message1); //Declares del and initializes it to point to method Message1
del += Message2; //Now method Message2 also gets added to del. Del is now pointing to two methods, Message1 and Message2. So it is now a MultiCast Delegate
del += Message3; //Method Message3 now also gets added to del
del(); //Del invokes Message1, Message2 and Message3 in the same order as they were added
/*
Output:
This is Message1
This is Message2
This is Message3
*/
del -= Message1; //Method Message1 is now removed from Del. It no longer points to Message1
//Del invokes the two remaining Methods Message1 and Message2 in the same order
del();
/*
New Output:
This is Message2
This is Message3
*/
del += Message4; //Method Message4 gets added to Del. The three Methods that Del oints to are in the order 1 -> Message2, 2 -> Message3, 3 -> Message4
//Del invokes the three methods in the same order in which they are present.
del();
/*
New Output:
This is Message2
This is Message3
This is Message4
*/
}
public static void Message1()
{
Console.WriteLine ("This is Message1");
}
public static void Message2()
{
Console.WriteLine ("This is Message2");
}
public static void Message3()
{
Console.WriteLine ("This is Message3");
}
public static void Message4()
{
Console.WriteLine ("This is Message4");
}
}
Tipo 2:
0 argumentos y tipo int retorno delegado
Método 1-
using System;
delegate int SampleDelagate();
class MainClass
{
public static void Main()
{
SampleDelagate del1 = new SampleDelagate (Method1);
SampleDelagate del2 = new SampleDelagate (Method2);
SampleDelagate del3 = new SampleDelagate (Method3);
SampleDelagate del4 = del1 + del2 + del3;
int ValueReturned = del4();
//Del4 invokes Del1, Del2, Del3 in the same order. Here the return type is int. So the return of last delegate del3 is returned. Del3 points to Method3. So returned value is 3.
Console.WriteLine (ValueReturned);
//Output: 3
}
public static int Method1()
{
return 1;
}
public static int Method2()
{
return 2;
}
public static int Method3()
{
return 3;
}
}
Método 2-
mismo proceso como Tipo 1
Entonces, cuando hay un tipo de devolución de un Delegado MultiCast, el valor de retorno es el valor de retorno del último delegado.
Tipo 3:
int, int, ref argumentos int y sin efecto tipo de retorno delegado -
using System;
delegate void SampleDelegate (ref int SampleReferenceParameter);
class MainClass
{
public static void Main()
{
SampleDelegate del1, del2, del3, del4;
del1 = new SampleDelegate (SampleMethodOne);
del2 = new SampleDelegate (SampleMethodTwo);
del3 = new SampleDelegate (SampleMethodTwo);
del4 = del1 + del2 + del3 - del3;
int SampleReferenceParameterValue = 0;
del4 (ref SampleReferenceParameterValue);
Console.WriteLine (SampleReferenceParameterValue);
}
public static void SampleMethodOne (ref int SampleReferenceParameter)
{
SampleReferenceParameter = 1;
}
public static void SampleMethodTwo (ref int SampleReferenceParameter)
{
SampleReferenceParameter = 2;
}
public static void SampleMethodThree (ref int SampleReferenceParameter)
{
SampleReferenceParameter = 3;
}
}
/*
Here del4 is first set as sum of del1, del2 and del3. Then del3 is subtracted from del4. So del4 now has del1, del2.
When del4 is invoked, first del1 and then del2 is invoked.
del1 sets reference parameter to 1. del2 sets reference parameter to 2.
But since del2 is called last final value of reference parameter is 2
*/
son delegados de multidifusión nada más que delegados normales que tienen varias referencias de métodos en su lista de invocación? – A9S6
Exactamente. Un delegado de multidifusión invocará múltiples métodos. –
OK. Solo para dejarlo más claro: declaro un delegado normal y agrego un método ref, ahora esto se llamará un delegado Singlecast. Ahora agrego otro método al mismo delegado, ¿esto ahora será referido como un delegado de multidifusión? – A9S6