¿Cómo obtener el último día de la semana pasada en sql?

Question

¿Cómo obtener la última fecha de la última semana en sql? Me refiero a la última fecha de domingo con la consulta?

Answer 1

Independientemente del ajuste DATEFIRST real, el último domingo se pudo encontrar la siguiente manera:

SELECT DATEADD(day, 
       -1 - (DATEPART(weekday, GETDATE()) + @@DATEFIRST - 2) % 7, 
       GETDATE() 
      ) AS LastSunday 

Reemplazar GETDATE() con un parámetro @date para obtener el último domingo antes de una fecha en particular.

Answer 2

SET @EndDate = GETDATE()-DatePart(dw, GETDATE()); 

Answer 3

Aquí está un gran artículo sobre cómo hacer esto:

http://www.objectreference.net/post/SQL-Find-last-week-date-range.aspx

Usted desea utilizar la variable @StartOfPrevWeek.

Answer 4

domingo pasado (¿Cuál es el fin de "la semana pasada")

SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6) AS LAST_SUNDAY 

esta semana (Suponiendo LD Semana Formato)

SELECT DATEADD(wk, DATEDIFF(wk, 7, CURRENT_TIMESTAMP), 7) AS START_OF_WEEK 
SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6 + 7) AS END_OF_WEEK 

Resultados

START_OF_WEEK 
----------------------- 
2011-05-02 00:00:00.000 

END_OF_WEEK 
----------------------- 
2011-05-08 00:00:00.000 

ejemplos para explicar el vudú (usar esto para hacer cambios en las SQL para su partir de la semana que desee y Semana que termina el día de la semana los) días

• Los ejemplos a continuación localizar de la semana dentro de la semana actual (domingo a sábado)
• Si el END_OF_WEEK real es la próxima semana de domingo a sábado, entonces necesita +7 al valor de esta semana. (. Vea el ejemplo END_OF_WEEK anterior)

SQL A continuación

SELECT DATEADD(wk, DATEDIFF(wk, -2, CURRENT_TIMESTAMP), -2) AS DAY_OF_WEEK /* Saturday */ 
SELECT DATEADD(wk, DATEDIFF(wk, -1, CURRENT_TIMESTAMP), -1) AS DAY_OF_WEEK /* Sunday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 0, CURRENT_TIMESTAMP), 0) AS DAY_OF_WEEK /* Monday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 1, CURRENT_TIMESTAMP), 1) AS DAY_OF_WEEK /* Tuesday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 2, CURRENT_TIMESTAMP), 2) AS DAY_OF_WEEK /* Wednesday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 3, CURRENT_TIMESTAMP), 3) AS DAY_OF_WEEK /* Thursday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 4, CURRENT_TIMESTAMP), 4) AS DAY_OF_WEEK /* Friday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 5, CURRENT_TIMESTAMP), 5) AS DAY_OF_WEEK /* Saturday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6) AS DAY_OF_WEEK /* Sunday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 7, CURRENT_TIMESTAMP), 7) AS DAY_OF_WEEK /* Monday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 8, CURRENT_TIMESTAMP), 8) AS DAY_OF_WEEK /* Tuesday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 9, CURRENT_TIMESTAMP), 9) AS DAY_OF_WEEK /* Wednesday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 10, CURRENT_TIMESTAMP), 10) AS DAY_OF_WEEK /* Thursday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 11, CURRENT_TIMESTAMP), 11) AS DAY_OF_WEEK /* Friday */ 
SELECT DATEADD(wk, DATEDIFF(wk, 12, CURRENT_TIMESTAMP), 12) AS DAY_OF_WEEK /* Saturday */ 
etc... 

Answer 5

El SQL es más sencillo con una tabla de calendario adecuada. Sin vudú.

select max(cal_date) end_of_last_week 
from calendar 
where (cal_date < current_date and day_of_week = 'Sun'); 

end_of_last_week 
-- 
2011-05-01 

Answer 6

SELECT (DATEADD(DAY, ((DATEPART(dw, @Date) - 1) * -1), @Date)) 

Answer 7

DECLARE @LastSunday DATETIME 

-- This will get the previous Sunday with time as 23:59:59 
SELECT @LastSunday = Dateadd(SECOND, -1, Dateadd(WK, Datediff(WK, 6, 
                CURRENT_TIMESTAMP) 
               , 7)) 

SELECT @LastSunday 

-- This gets the monday prior to it and time of 00:00:00 
SELECT Dateadd(SECOND, 1, Dateadd(DAY, -7, @LastSunday)) 
-- This will make you time spans between eg, Monday 16/07/2012 00:00:00 through to Sunday 22/07/2012 23:59:59 
-- Then use them in your WHERE clause like this 
-- SELECT X,Y,Z From SomeTable 
-- WHERE DateField BETWEEN @PreviousMondayToLastSunday AND @LastSunday 

Answer 8

Esto obtendrá la siguiente y preciosa viernes de una fecha y hora determinada

DECLARE @PREVIOUS int, @dtmStart datetime,@dtmEnd datetime, @NEXT int; 
SET @dtmStart = '12/10/2013'; 
SET @dtmEnd = '12/11/2013'; 

select @PREVIOUS = datepart(dw,@dtmStart) 
WHILE @PREVIOUS <> 6 
BEGIN 
    SET @dtmStart = DATEADD(day , -1 ,@dtmStart) 
    SET @PREVIOUS = datepart(dw,@dtmStart) 
    CONTINUE 
END 
select @dtmStart 

SELECT @NEXT = DATEPART(dw, @dtmEnd) 
    WHILE @NEXT <> 6 
BEGIN 
    SET @dtmEnd = DATEADD(day , 1 ,@dtmEnd) 
    SET @NEXT = datepart(dw,@dtmEnd) 
    CONTINUE 
END 
select @dtmEnd 

Answer 9

Para obtener el Domingo anterior o actual, si hoy es domingo, intente esto

DATEADD(day,- (DATEPART(dw,getdate()) + @@DATEFIRST -1) % 7, getdate()) 

Answer 10

Aquí está el código para obtener la fecha del último Saturd sí. Este método es independiente de la configuración de la base de datos.

declare @lastSaturday date, 
     @today date, 
     @todayName varchar(20); 

select @todayName = datename(weekday, getdate()), @today = getdate(); 

select 
      case @todayName 
       when 'Saturday' then @today 
       when 'Sunday' then dateadd(day,-1,@today) 
       when 'Monday' then dateadd(day,-2,@today) 
       when 'Tuesday' then dateadd(day,-3,@today) 
       when 'Wednesday' then dateadd(day,-4,@today) 
       when 'Thursday' then dateadd(day,-5,@today) 
       when 'Friday' then dateadd(day,-6,@today) 
      end as LastSaturday;