android.os.NetworkOnMainThreadException. ¿Necesita usar una tarea asincrónica?

Question

Estoy teniendo un problema con mi funcionalidad de inicio de sesión androide, conseguir android.os.NetworkOnMainThreadException

Quité el campo de la contraseña sólo por ahora de probar si sólo el nombre de usuario se está publicando, soy consciente de que este es un problema para android 3.2 +.

Aquí está mi código:

package com.example.toknapp; 

import java.util.ArrayList; 

public class login2 extends Activity { 
    EditText un; 
    TextView error; 
    Button ok; 
    /** Called when the activity is first created. */ 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.login); 
     un=(EditText)findViewById(R.id.et_un); 
     ok=(Button)findViewById(R.id.btn_login); 
     error=(TextView)findViewById(R.id.tv_error); 

     ok.setOnClickListener(new View.OnClickListener() { 

      @Override 
      public void onClick(View v) { 
       // TODO Auto-generated method stub 

       ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); 
       postParameters.add(new BasicNameValuePair("username", un.getText().toString())); 
       //String valid = "1"; 
       String response = null; 
       try { 
        response = CustomHttpClient.executeHttpPost("http://tokn.me/android_merchant_login.php", postParameters); 
        String res=response.toString(); 
        // res = res.trim(); 
        res= res.replaceAll("\\s+","");        
        //error.setText(res); 

        if(res.equals("1")) 
         error.setText("Correct Username or Password"); 
        else 
         error.setText("Sorry!! Incorrect Username or Password"); 
       } catch (Exception e) { 
        un.setText(e.toString()); 
       } 

      } 
     }); 
    } 
} 


package com.example.toknapp; 

import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.net.URI; 
import java.util.ArrayList; 

import org.apache.http.HttpResponse; 
import org.apache.http.NameValuePair; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.entity.UrlEncodedFormEntity; 
import org.apache.http.client.methods.HttpGet; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.conn.params.ConnManagerParams; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.apache.http.params.HttpConnectionParams; 
import org.apache.http.params.HttpParams; 

public class CustomHttpClient { 
    /** The time it takes for our client to timeout */ 
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds 

    /** Single instance of our HttpClient */ 
    private static HttpClient mHttpClient; 

    /** 
    * Get our single instance of our HttpClient object. 
    * 
    * @return an HttpClient object with connection parameters set 
    */ 
    private static HttpClient getHttpClient() { 
     if (mHttpClient == null) { 
      mHttpClient = new DefaultHttpClient(); 
      final HttpParams params = mHttpClient.getParams(); 
      HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT); 
      HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT); 
      ConnManagerParams.setTimeout(params, HTTP_TIMEOUT); 
     } 
     return mHttpClient; 
    } 

    /** 
    * Performs an HTTP Post request to the specified url with the 
    * specified parameters. 
    * 
    * @param url The web address to post the request to 
    * @param postParameters The parameters to send via the request 
    * @return The result of the request 
    * @throws Exception 
    */ 
    public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception { 
     BufferedReader in = null; 
     try { 
      HttpClient client = getHttpClient(); 
      HttpPost request = new HttpPost(url); 
      UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); 
      request.setEntity(formEntity); 
      HttpResponse response = client.execute(request); 
      in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 

      StringBuffer sb = new StringBuffer(""); 
      String line = ""; 
      String NL = System.getProperty("line.separator"); 
      while ((line = in.readLine()) != null) { 
       sb.append(line + NL); 
      } 
      in.close(); 

      String result = sb.toString(); 
      return result; 
     } finally { 
      if (in != null) { 
       try { 
        in.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 

    /** 
    * Performs an HTTP GET request to the specified url. 
    * 
    * @param url The web address to post the request to 
    * @return The result of the request 
    * @throws Exception 
    */ 
    public static String executeHttpGet(String url) throws Exception { 
     BufferedReader in = null; 
     try { 
      HttpClient client = getHttpClient(); 
      HttpGet request = new HttpGet(); 
      request.setURI(new URI(url)); 
      HttpResponse response = client.execute(request); 
      in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 

      StringBuffer sb = new StringBuffer(""); 
      String line = ""; 
      String NL = System.getProperty("line.separator"); 
      while ((line = in.readLine()) != null) { 
       sb.append(line + NL); 
      } 
      in.close(); 

      String result = sb.toString(); 
      return result; 
     } finally { 
      if (in != null) { 
       try { 
        in.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 
} 

Answer 1

Creo que se está tratando de peform alguna operación de red en el hilo principal

NetworkOnMainThreadException de los Documentos

La excepción que se produce cuando una aplicación intenta realizar una operación de red en su hilo principal.

ACTUALIZACIÓN:

que es mejor usar AsyncTask

private class MyAsyncTask extends AsyncTask<Void, Void, Void> 
    { 

     ProgressDialog mProgressDialog; 
     @Override 
     protected void onPostExecute(Void result) { 
      mProgressDialog.dismiss(); 
     } 

     @Override 
     protected void onPreExecute() { 
      mProgressDialog = ProgressDialog.show(ActivityName.this, 
              "Loading...", "Data is Loading..."); 
     } 

     @Override 
     protected Void doInBackground(Void... params) { 
      // your network operation 
      return null; 
     } 
    } 

Answer 2

Selecciona esta link. describe todo lo que necesitarás hacer.

[editar]

Parece que cambiaron la página. Este link le mostrará cómo usar tareas asincrónicas

Answer 3

Simplemente cambie la versión de destino en el archivo de manifiesto a lover que Honeycomb.

<uses-sdk 
    android:minSdkVersion="8" 
    android:targetSdkVersion="8" /> 

Editar: Pero el uso de AsyncTask es la manera más conveniente de resolver este problema.